(32^(2/5))*(4x)*((1/x)^2)

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Solution for (32^(2/5))*(4x)*((1/x)^2) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*32^(2/5)*(1/x)^2*x = 0

16*x^-1 = 0 // : 16

x^-1 = 0

x należy do O

x belongs to the empty set

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